NO

Initial ITS
Start location: __init
   0: f1_0_main_ConstantStackPush -> f40_0_sum_InvokeMethod : arg2'=arg2P0, arg1'=arg1P0, (2+arg2 > 0 /\ arg2 >= 0 /\ -2-arg2P0-arg2 == 0 /\ 1+arg2 > 0 /\ arg1 > 0 /\ -1-arg2-arg1P0 == 0), cost: 1
   1: f40_0_sum_InvokeMethod -> f40_0_sum_InvokeMethod : arg2'=arg2P1, arg1'=arg1P1, (arg2 < 0 /\ arg2-arg1 < 0 /\ -1+arg2 < 0 /\ -1+arg2-arg2P1 == 0 /\ arg2-arg1P1 == 0 /\ -1+arg1 < 0), cost: 1
   2: __init -> f1_0_main_ConstantStackPush : arg2'=arg2P2, arg1'=arg1P2, TRUE, cost: 1


Applied preprocessing
Original rule:
f1_0_main_ConstantStackPush -> f40_0_sum_InvokeMethod : arg2'=arg2P0, arg1'=arg1P0, (2+arg2 > 0 /\ arg2 >= 0 /\ -2-arg2P0-arg2 == 0 /\ 1+arg2 > 0 /\ arg1 > 0 /\ -1-arg2-arg1P0 == 0), cost: 1
New rule:
f1_0_main_ConstantStackPush -> f40_0_sum_InvokeMethod : arg2'=-2-arg2, arg1'=-1-arg2, (1+arg2 > 0 /\ arg1 > 0), cost: 1

Applied preprocessing
Original rule:
f40_0_sum_InvokeMethod -> f40_0_sum_InvokeMethod : arg2'=arg2P1, arg1'=arg1P1, (arg2 < 0 /\ arg2-arg1 < 0 /\ -1+arg2 < 0 /\ -1+arg2-arg2P1 == 0 /\ arg2-arg1P1 == 0 /\ -1+arg1 < 0), cost: 1
New rule:
f40_0_sum_InvokeMethod -> f40_0_sum_InvokeMethod : arg2'=-1+arg2, arg1'=arg2, (-arg2+arg1 > 0 /\ 1-arg1 > 0), cost: 1

Simplified rules
Start location: __init
   3: f1_0_main_ConstantStackPush -> f40_0_sum_InvokeMethod : arg2'=-2-arg2, arg1'=-1-arg2, (1+arg2 > 0 /\ arg1 > 0), cost: 1
   4: f40_0_sum_InvokeMethod -> f40_0_sum_InvokeMethod : arg2'=-1+arg2, arg1'=arg2, (-arg2+arg1 > 0 /\ 1-arg1 > 0), cost: 1
   2: __init -> f1_0_main_ConstantStackPush : arg2'=arg2P2, arg1'=arg1P2, TRUE, cost: 1


Applied nonterm
Original rule:
f40_0_sum_InvokeMethod -> f40_0_sum_InvokeMethod : arg2'=-1+arg2, arg1'=arg2, (-arg2+arg1 > 0 /\ 1-arg1 > 0), cost: 1
New rule:
f40_0_sum_InvokeMethod -> [3] : (-1+n >= 0 /\ -arg2+arg1 > 0 /\ 1-arg1 > 0), cost: NONTERM
Sub-proof via acceration calculus written to file:///tmp/tmpnam_mnmFFL.txt

Applied deletion
Removed the following rules: 4

Accelerated simple loops
Start location: __init
   3: f1_0_main_ConstantStackPush -> f40_0_sum_InvokeMethod : arg2'=-2-arg2, arg1'=-1-arg2, (1+arg2 > 0 /\ arg1 > 0), cost: 1
   5: f40_0_sum_InvokeMethod -> [3] : (-1+n >= 0 /\ -arg2+arg1 > 0 /\ 1-arg1 > 0), cost: NONTERM
   2: __init -> f1_0_main_ConstantStackPush : arg2'=arg2P2, arg1'=arg1P2, TRUE, cost: 1


Applied chaining
First rule:
f1_0_main_ConstantStackPush -> f40_0_sum_InvokeMethod : arg2'=-2-arg2, arg1'=-1-arg2, (1+arg2 > 0 /\ arg1 > 0), cost: 1
Second rule:
f40_0_sum_InvokeMethod -> [3] : (-1+n >= 0 /\ -arg2+arg1 > 0 /\ 1-arg1 > 0), cost: NONTERM
New rule:
f1_0_main_ConstantStackPush -> [3] : (1+arg2 > 0 /\ arg1 > 0), cost: NONTERM

Applied deletion
Removed the following rules: 5

Chained accelerated rules with incoming rules
Start location: __init
   3: f1_0_main_ConstantStackPush -> f40_0_sum_InvokeMethod : arg2'=-2-arg2, arg1'=-1-arg2, (1+arg2 > 0 /\ arg1 > 0), cost: 1
   6: f1_0_main_ConstantStackPush -> [3] : (1+arg2 > 0 /\ arg1 > 0), cost: NONTERM
   2: __init -> f1_0_main_ConstantStackPush : arg2'=arg2P2, arg1'=arg1P2, TRUE, cost: 1


Removed unreachable locations and irrelevant leafs
Start location: __init
   6: f1_0_main_ConstantStackPush -> [3] : (1+arg2 > 0 /\ arg1 > 0), cost: NONTERM
   2: __init -> f1_0_main_ConstantStackPush : arg2'=arg2P2, arg1'=arg1P2, TRUE, cost: 1


Eliminating location f1_0_main_ConstantStackPush by chaining:

Applied chaining
First rule:
__init -> f1_0_main_ConstantStackPush : arg2'=arg2P2, arg1'=arg1P2, TRUE, cost: 1
Second rule:
f1_0_main_ConstantStackPush -> [3] : (1+arg2 > 0 /\ arg1 > 0), cost: NONTERM
New rule:
__init -> [3] : (arg1P2 > 0 /\ 1+arg2P2 > 0), cost: NONTERM

Applied deletion
Removed the following rules: 2 6

Eliminated locations on linear paths
Start location: __init
   7: __init -> [3] : (arg1P2 > 0 /\ 1+arg2P2 > 0), cost: NONTERM


Computing asymptotic complexity
Proved nontermination of rule 7 via SMT.

Proved the following lower bound
Complexity:  Nonterm
Cpx degree: Nonterm

Solved cost: NONTERM
Rule cost:   NONTERM
Rule guard:  (arg1P2 > 0 /\ 1+arg2P2 > 0)