YES

Solver Timeout: 4
Global Timeout: 300
No parsing errors!
Init Location: 0
Transitions:
<l0, l11, true>
<l1, l2, ((0 + k^0) <= 100) /\ (undef5 = undef5), par{i^0 -> 0, tmp___0^0 -> undef5}>
<l1, l3, (101 <= (0 + k^0))>
<l4, l1, (1 <= (0 + k^0))>
<l4, l3, ((0 + k^0) <= 0)>
<l2, l5, true>
<l6, l3, ((0 + i^0) <= (0 + j^0))>
<l6, l7, ((1 + j^0) <= (0 + i^0)), par{j^0 -> (1 + j^0)}>
<l8, l7, true, par{i^0 -> (~(1) + i^0), j^0 -> 0}>
<l7, l6, true>
<l9, l2, true, par{i^0 -> (1 + i^0)}>
<l9, l8, true>
<l5, l8, ((0 + i^0) <= (0 + k^0)) /\ ((0 + k^0) <= (0 + i^0))>
<l5, l9, ((1 + k^0) <= (0 + i^0))>
<l5, l9, ((1 + i^0) <= (0 + k^0))>
<l10, l4, (undef74 = undef74), par{k^0 -> (0 + undef74), tmp^0 -> undef74}>
<l11, l10, true>

Fresh variables:
undef5, undef74, 

Undef variables:
undef5, undef74, 

Abstraction variables:

Exit nodes:

Accepting locations:

Asserts:

Preprocessed LLVMGraph
Init Location: 0
Transitions:
<l0, l2, (k^0 = (0 + undef74)) /\ (undef74 = undef74) /\ (1 <= (0 + (0 + undef74))) /\ ((0 + (0 + undef74)) <= 100) /\ (undef5 = undef5), par{i^0 -> 0}>
<l0, l3, (k^0 = (0 + undef74)) /\ (undef74 = undef74) /\ (1 <= (0 + (0 + undef74))) /\ (101 <= (0 + (0 + undef74)))>
<l0, l3, (k^0 = (0 + undef74)) /\ (undef74 = undef74) /\ ((0 + (0 + undef74)) <= 0)>
<l2, l7, ((0 + i^0) <= (0 + k^0)) /\ ((0 + k^0) <= (0 + i^0)), par{i^0 -> (~(1) + i^0), j^0 -> 0}>
<l2, l2, ((1 + k^0) <= (0 + i^0)), par{i^0 -> (1 + i^0)}>
<l2, l7, ((1 + k^0) <= (0 + i^0)), par{i^0 -> (~(1) + i^0), j^0 -> 0}>
<l2, l2, ((1 + i^0) <= (0 + k^0)), par{i^0 -> (1 + i^0)}>
<l2, l7, ((1 + i^0) <= (0 + k^0)), par{i^0 -> (~(1) + i^0), j^0 -> 0}>
<l7, l3, ((0 + i^0) <= (0 + j^0))>
<l7, l7, ((1 + j^0) <= (0 + i^0)), par{j^0 -> (1 + j^0)}>

Fresh variables:
undef5, undef74, 

Undef variables:
undef5, undef74, 

Abstraction variables:

Exit nodes:

Accepting locations:

Asserts:

*************************************************************
*******************************************************************************************
***********************       WORKING TRANSITION SYSTEM (DAG)       ***********************
*******************************************************************************************

Init Location: 0
Graph 0:
Transitions:
Variables:

Graph 1:
Transitions:
<l2, l2, 1 + k^0 <= i^0, {i^0 -> 1 + i^0, rest remain the same}>
<l2, l2, 1 + i^0 <= k^0, {i^0 -> 1 + i^0, rest remain the same}>
Variables:
i^0, k^0

Graph 2:
Transitions:
<l7, l7, 1 + j^0 <= i^0, {j^0 -> 1 + j^0, rest remain the same}>
Variables:
i^0, j^0

Graph 3:
Transitions:
Variables:

Precedence: 
Graph 0

Graph 1
<l0, l2, 1 <= undef74 /\ undef74 <= 100 /\ k^0 = undef74, {i^0 -> 0, rest remain the same}>

Graph 2
<l2, l7, i^0 = k^0, {i^0 -> -1 + i^0, j^0 -> 0, rest remain the same}>
<l2, l7, 1 + k^0 <= i^0, {i^0 -> -1 + i^0, j^0 -> 0, rest remain the same}>
<l2, l7, 1 + i^0 <= k^0, {i^0 -> -1 + i^0, j^0 -> 0, rest remain the same}>

Graph 3
<l0, l3, 101 <= undef74 /\ k^0 = undef74, {all remain the same}>
<l0, l3, undef74 <= 0 /\ k^0 = undef74, {all remain the same}>
<l7, l3, i^0 <= j^0, {all remain the same}>

Map Locations to Subgraph:
( 0 , 0 )
( 2 , 1 )
( 3 , 3 )
( 7 , 2 )

*******************************************************************************************
********************************    CHECKING ASSERTIONS    ********************************
*******************************************************************************************

Proving termination of subgraph 0
Proving termination of subgraph 1
Checking unfeasibility...
Time used: 0.002953
Some transition disabled by a set of invariant(s):
Invariant at l2: i^0 <= k^0

Strengthening and disabling transitions...
> It's unfeasible. Removing transition: 
<l2, l2, 1 + k^0 <= i^0, {i^0 -> 1 + i^0, rest remain the same}>

LOG: CALL solverLinear in Graph for feasibility

LOG: RETURN solveLinear in Graph for feasibility
Strengthening transition (result): 
<l2, l2, 1 + i^0 <= k^0, {i^0 -> 1 + i^0, rest remain the same}>
Checking unfeasibility...
Time used: 0.001089

Checking conditional termination of SCC {l2}...

LOG: CALL solveLinear

LOG: RETURN solveLinear - Elapsed time: 0.000506s
Ranking function: -1 - i^0 + k^0
New Graphs: 
Proving termination of subgraph 2
Checking unfeasibility...
Time used: 0.001351

Checking conditional termination of SCC {l7}...

LOG: CALL solveLinear

LOG: RETURN solveLinear - Elapsed time: 0.000518s
Ranking function: -1 + i^0 - j^0
New Graphs: 
Proving termination of subgraph 3
Analyzing SCC {l3}...
No cycles found.

Program Terminates