YES

Solver Timeout: 4
Global Timeout: 300
No parsing errors!
Init Location: 0
Transitions:
<l0, l3, true>
<l1, l2, (undef2 > ~(1)) /\ (undef1 > 0) /\ (arg2 > ~(1)) /\ (arg1 > 0), par{arg1 -> undef1, arg2 -> undef2}>
<l2, l2, (arg2 < arg1) /\ (arg1 > 0) /\ (arg2 > ~(1)), par{arg2 -> (arg1 + arg2)}>
<l3, l1, true, par{arg1 -> undef5, arg2 -> undef6}>

Fresh variables:
undef1, undef2, undef5, undef6, 

Undef variables:
undef1, undef2, undef5, undef6, 

Abstraction variables:

Exit nodes:

Accepting locations:

Asserts:

Preprocessed LLVMGraph
Init Location: 0
Transitions:
<l0, l2, (arg1 = undef1) /\ (arg2 = undef2) /\ (undef2 > ~(1)) /\ (undef1 > 0) /\ (undef6 > ~(1)) /\ (undef5 > 0)>
<l2, l2, (arg2 < arg1) /\ (arg1 > 0) /\ (arg2 > ~(1)), par{arg2 -> (arg1 + arg2)}>

Fresh variables:
undef1, undef2, undef5, undef6, 

Undef variables:
undef1, undef2, undef5, undef6, 

Abstraction variables:

Exit nodes:

Accepting locations:

Asserts:

*************************************************************
*******************************************************************************************
***********************       WORKING TRANSITION SYSTEM (DAG)       ***********************
*******************************************************************************************

Init Location: 0
Graph 0:
Transitions:
Variables:

Graph 1:
Transitions:
<l2, l2, 1 <= arg1 /\ 1 + arg2 <= arg1 /\ 0 <= arg2, {arg2 -> arg1 + arg2, rest remain the same}>
Variables:
arg1, arg2

Precedence: 
Graph 0

Graph 1
<l0, l2, 1 <= undef1 /\ 1 <= undef5 /\ 0 <= undef2 /\ 0 <= undef6 /\ arg1 = undef1 /\ arg2 = undef2, {all remain the same}>

Map Locations to Subgraph:
( 0 , 0 )
( 2 , 1 )

*******************************************************************************************
********************************    CHECKING ASSERTIONS    ********************************
*******************************************************************************************

Proving termination of subgraph 0
Proving termination of subgraph 1
Checking unfeasibility...
Time used: 0.002162

Checking conditional termination of SCC {l2}...

LOG: CALL solveLinear

LOG: RETURN solveLinear - Elapsed time: 0.000743s
Ranking function: -1 + arg1 - arg2
New Graphs: 
Program Terminates